1.

0.01 m aqueous solution of K_(3)[Fe(CN)_(6)] freezes at -0.062^(@)C. What is the apparent percentage of dissociation ? (K_(f)" for water = 1.86 K kg mol"^(-1))

Answer»


Solution :`DeltaT_(f)"(observed)"=0.062^(@)C`
`DeltaT_(f)"(CALCULATED)"=K_(f)xxm=1.86xx0.01=0.0186^(@)C`
`therefore""i=(DeltaT_(f)"(observed)")/(DeltaT_(f)"(calculated)")=(0.062)/(0.0186)=3.33`
`{:(,""K_(3)[Fe(CN)_(6)]hArr3K^(+)+[Fe(CN)_(6)]^(3-)),("Initial","1 MOL "),("After disso.",""1-ALPHA""3alpha ""alpha "Total "= 1+3alpha):}`
`therefore""i=(1+3alpha)/(1) or alpha=(i-1)/(3)=(3.33-1)/(3)=0.777=77.7%`.


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