0.01 solution of NaCl offered a resistance of 200 Ohm in a conductivit

1.	0.01 solution of NaCl offered a resistance of 200 Ohm in a conductivity cell at 298 Kelvin if the cell constant of the cell is unity calculate molar conductivity of the solution.
Answer» Answer: κ = R cellconstant κ = 200^1 ∧ m =κ M1000 ∧ m = 0.01∗200^1000 ^ m = 500 Scm 2 MOL −1 hope it will help you ❣️❣️ please SEND me your message

0.01 solution of NaCl offered a resistance of 200 Ohm in a conductivity cell at 298 Kelvin if the cell constant of the cell is unity calculate molar conductivity of the solution.

Answer»

Answer:

κ =

cellconstant

κ = 200^1

∧ m =κ M1000

∧ m = 0.01∗200^1000

^ m = 500 Scm 2 MOL −1

hope it will help you ❣️❣️

please SEND me your message

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0.01 solution of NaCl offered a resistance of 200 Ohm in a conductivity cell at 298 Kelvin if the cell constant of the cell is unity calculate molar conductivity of the solution.​

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0.01 solution of NaCl offered a resistance of 200 Ohm in a conductivity cell at 298 Kelvin if the cell constant of the cell is unity calculate molar conductivity of the solution.