0.014 g of nitrogen is enclosed in a vessel at a temperature of 27^(@)C. How much heat (in J) approximately has to be transferred to the gas to double the rms velocity of its molecules?

0.014 g of nitrogen is enclosed in a vessel at a temperature of 27^(@)

1.	0.014 g of nitrogen is enclosed in a vessel at a temperature of 27^(@)C. How much heat (in J) approximately has to be transferred to the gas to double the rms velocity of its molecules?
Answer» 930 212 9 6 Solution :We have `(v_(1))/(v_(2))=SQRT((T_(1))/(T_(2)))therefore (1)/(2)=sqrt((T_(1))/(T_(2)))` or `T_(2)=4T_(1) therefore DeltaT=T_(2)-T_(1)=3T_(1)=3xx(273+27)=900K` The heat REQUIRED, `Q=muC_(V)DeltaT` `=[(14)/(28)]XX(5)/(2)xx(8.31xx900)/(1000)=9.315J~=9J`

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0.014 g of nitrogen is enclosed in a vessel at a temperature of 27^(@)C. How much heat (in J) approximately has to be transferred to the gas to double the rms velocity of its molecules?

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