1.

0.02 M monobasic acid dissociates 2% hence, pH of the solution is

Answer»

0.3979
1.3979
1.699
3.3979

Solution :`[H^(+)] = alpha.C = (2)/(100) xx 0.2, [H^(+)] = 4 xx 10^(-4)M`
`pH = -log [H^(+)] = 4 -log 4 , pH = 33979`.


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