1.

0.02 mole of [Co(NH_(3))_(5)Br]Cl_(2) and 0.02 mole of [Co(NH_(3))_(5) Cl] SO_(4) are present in 200 cc of a solution X . The number of moles of the precipitates Y and Z that are formed when the solution X is treated with excess silver nitrate and excess barium chloride are respectively

Answer»

0.02 , 0.02
0.01 , 0.02
0.02 , 0.04
0.04 , 0.02

Solution :`[Counderset(0.02 "mole") underset(1"mole") ((NH_(3))_(5))Br]Cl_(2) + 2 underset(2 "MOLES")(AgNO_(3)) to [Co(NH_(3))_(5)underset(1 "mole")(Br)](NO_(3))_(2) + 2 Agunderset(2 "moles")(Cl)_((PPT)) (Y)`
`0.02 xx 2 = 0.04 ` mole
`[Co(NH_(3))_(5)underset(1 "mole")(Cl)]SO_(4) + underset(0.02 "moles")(BaCl_(2)) to [Co(NH_(3))_(5)underset(1 "mole")(Cl)] Cl_(2) + BaSO_(4)_("(ppt.)") underset(0.02 "moles")((Z))`


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