1.

0.023g of sodium metal is reacted with 100 cm^(3) of water. The pH of the resulting solution is :

Answer»

10
11
9
12

Solution :`M=(0.023xx1000)/(23xx100)=0.01M`
`NA^(+)+OH^(-)hArrNaOH`
`[OH^(-)]=0.01M=10^(-2)M," "pOH=-log(10^(-2))=2`
`pH+pOH=14`
`:." "pH=14-2rArrpH=12`.


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