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`0.05` moles of `NaHCO_(3)` will react with how many equivalent of `Mg(OH)_(2)`?A. `0.2 Eq.`B. `0.05 Eq.`C. `0.02 Eq.`D. `0.01 Eq.` |
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Answer» Correct Answer - B `0.05` equivalent or mole of `NaHCO_(3)` requires `0.05` eq. of `Mg(OH)_(2)`. `2NaHCO_(3)+Mg(OH)_(2)rarrMgCO_(3)+Na_(2)CO_(3)+2H_(2)O` |
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