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The density of `1 M` solution of `NaCl` is `1.0585 g mL^(-1)`. The molality of the solution isA. `1.0585`B. `1.0`C. `0.10`D. `0.0585` |
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Answer» Correct Answer - B `m=("Mole of" NaCl)/("weight of solvent in" kg)=(1)/(1)=1` `"wt. of solvent"="wt.of solution"-"wt. of" NaCl` `=1.0585xx1000-58.5` `=1058.5-58.5=100 g=1kg` |
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