`0.0755 g` of selenium vapours occupying a volume of `114.2 mL` at `700^(@)C` and `185 mm` of `Hg`. The vapours are in equilibrium as: `Se_(6(g))hArr3Se_(2(g))` Calculate: (`i`) Degree of dissociation of `Se`, (`ii`) `K_(p)`, (`iii`) `K_(c)`. Atomic weight of `Se` is `79`.

`0.0755 g` of selenium vapours occupying a volume of `114.2 mL` at `70

1.	`0.0755 g` of selenium vapours occupying a volume of `114.2 mL` at `700^(@)C` and `185 mm` of `Hg`. The vapours are in equilibrium as: `Se_(6(g))hArr3Se_(2(g))` Calculate: (`i`) Degree of dissociation of `Se`, (`ii`) `K_(p)`, (`iii`) `K_(c)`. Atomic weight of `Se` is `79`.
Answer» (`i`) `59%`, (`ii`) `0.168 atm`, (`iii`) `2.633xx10^(-5) mol^(2) litre^(-2)` ,

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`0.0755 g` of selenium vapours occupying a volume of `114.2 mL` at `700^(@)C` and `185 mm` of `Hg`. The vapours are in equilibrium as: `Se_(6(g))hArr3Se_(2(g))` Calculate: (`i`) Degree of dissociation of `Se`, (`ii`) `K_(p)`, (`iii`) `K_(c)`. Atomic weight of `Se` is `79`.

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