1.

0.0833 mol of carbohydrate of empirical formula CH_(2)O contain 1 gof hydrogen. The molecular formula of the carbohydrate is

Answer»

`C_(5)H_(10)O_(5)`
`C_(3)H_(4)O_(3)`
`C_(12)H_(22)O_(11)`
`C_(6)H_(12)O_(6)`

Solution :`:' 0.0833` mole carbohydrate has hydrogen `= 1g`
`:.` 1 mole carbohydrate has hydrogen
`= 1/(0.0833) =12g`
EMPIRICAL Formula `(CH_(2)O)` has hydrogen `= 2g`
Hence ` n = (12)/(2)= 6`
Hence molecular formula of carbohydrate `= 2g`
Hence `n = 12/2 =6`
Hence molecular formula of carbohydrate `= (CH_(2)O)_(6)`
`= C_(6)H_(12)O_(6)`.


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