1.

0.1 M HCl and 0.1 M H_(2)SO_(4), each of volume 2 ml are mixed and the volume is made up to 6 ml by adding 2ml of 0.01 N NaCl solution. The pH of the resulting mixture is

Answer»

1.17
`1.0`
0.3
log 2 - log 3

Solution :MILLIMOLES of `H^(+) = 0.1 xx 2 + 0.1 xx 2 xx 2 = 0.6`
TOTAL VOLUME in ML = 6
`pH = -log [H^(+)] = -log ((0.6)/(6)) = -log 0.1 = 1.0`.


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