1.

0.1 M NaOH was gradually added to 50 ml of aqueous of CH_(3)COOH.Find pH of the solution at the equivalent point of the reaction. [ log 5 = 0.70]

Answer»


Solution :CONCENTRATION of the salt formed
`(0.1 xx 50)/(100)= (0.1)/(2)= 0.05 [LOG C= log 5 xx 10^(-2)= 0.7 -2.0 = -1.30]`
`pH= 7+ (1)/(2) [pKa + log C]= 7 + (1)/(2) [4.7 +(-1.30)] =7 + (1)/(2) [3.40]= 8.70`


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