1.

0.1 " mol of "`MnO_(4)^(ɵ)` (in acidic medium) can:A. Oxidise 0.5 " mol of "`Fe^(2+)`B. Oxidise 0.166 " mol of "`FeC_(2)O_(4)`C. Oxidise 0.25 " mol of "`C_(2)O_(4)^(2-)`D. Oxidise 0.6 " mol of "`Cr_(2)O_(7)^(2-)`

Answer» Correct Answer - A::B::C
(a). `MnO_(4)^(ɵ)+8H^(o+)+5e^(-)toMn^(2-)+4H_(2)O`
`m" Eq of "MnO_(4)^(ɵ)=0.1xx5=0.5`
`Fe^(2+)toFe^(3+)+e^(-)`
`impliesm" Eq of "Fe^(2+)=0.5`
(b). `FeC_(2)O_(4)toFe^(3+)+2CO_(2)+3e^(-)`
`implies m" Eq of "FeC_(2)O_(4)=0.166xx3=0.5`
(d). `Cr_(2)O_(7)^(2-)` being an oxidising agent cannot be oxidised


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