1.

0.1 mole of N_(2)O_(4(g)) was sealed in a tube under one atmospheic conditions at 25^(@)C. Calculate the number of moles of NO_(2(g)) present, if the equlibrium N_(2)O_(4(g))hArr2NO_(2(g))(k_(p)=0.14) is reache3d after some time

Answer»

<P>`1.8xx10^(2)`
`2.8xx10^(2)`
`0.034`
`2.8xx10^(-2)`

Solution :`underset(0.1)(N_(2)O_(4))hArrunderset(0)(2NO_(2))`
`(.1-alpha)""2ALPHA`
`thereforeP prop0.1`
If V and T are constant `(Pprop0.1+alpha)P=(0.1+alpha)//0.1`
`K_(p)=([2alpha]^(2))/([0.1-alpha])xx[(P)/(0.1+alpha)]or K_(p)=(40alpha^(2))/([0.1-alpha])=0.14`
`alpha=0.017`
`NO_(2)=0.017xx2=0.034` MOLE


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