1.

0.126 g of an acid is needed to completely neutralise 20 mL 0.1 N NaOH solution. The equivalent weight of the acid is

Answer»

53
40
45
63

Solution :Equivalents of acid = Equivalents of base
`=(NV)/1000 =(0.1 XX 20)/1000 = 2 xx 10^(-3)`
No. of gram equivalents `=("mass")/("Equivalent mass")`
`2 xx 10^(-3) = 0.126/("Equivalent mass")`
Equivalent mass `=0.126/(2 xx 10^(-3)) = 126/2 = 63`


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