0.126 g of an acid requires 20 ml of 0.1 N NaOH for complete neutrails

1.	0.126 g of an acid requires 20 ml of 0.1 N NaOH for complete neutrailsa(2) 53(1) 45N NaOH for complete neutralisation. Eq. wt. of the acid is:(3) 40(4) 63
Answer» Answer:4)63 Explanation: 20 ml of 0.1 N NaOH is required to neutralise 0.126 g of acid So, 1000 ml of 0.1 NNaOH will neutralise =0.12620×10.1×1000g=63g Therefore, gram equivalent of acid =63 g

0.126 g of an acid requires 20 ml of 0.1 N NaOH for complete neutrailsa(2) 53(1) 45N NaOH for complete neutralisation. Eq. wt. of the acid is:(3) 40(4) 63

Answer»

Answer:4)63

Explanation:

20 ml of 0.1 N NaOH is required to neutralise 0.126 g of acid

So, 1000 ml of 0.1 NNaOH will neutralise =0.12620×10.1×1000g=63g

Therefore, gram equivalent of acid =63 g