1.

0.146g of an acid requires 20 ml of 0.1 N NaOH for complete neutralization. The equivalent weight of the acid is

Answer»

45
53
40
63

Solution :20 ML of 0.1N NaoH NEUTRALIZE 20 ml of 0.1 N acid weight of acid=0.126g
volume`=20ml=(20)/(1000)` litre
Normality`=0.1N,` EQUIVALENT weight=?
Equivalent weight`=("Weight of acid")/(NxxV)`
`=(0.126xx1000)/(0.1xx20)=63`


Discussion

No Comment Found

Related InterviewSolutions