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0-14A bullet of mass 10g moving with a velocity of 400m/s Embedded ina freely suspended wooden block of mass 900g. What is the velocityacquired by the block ? |
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Answer» By using law of conservation of momentumm₁u₁ = (m₁ + m₂)v v = m₁u₁ / (m₁ + m₂)= (10 × 10^-3 kg × 400 m/s) / [(10 + 900) × 10^-3 kg]= 4.395 m/s Velocity acquired by the wooden block is 4.395 m/s |
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