1.

0-14A bullet of mass 10g moving with a velocity of 400m/s Embedded ina freely suspended wooden block of mass 900g. What is the velocityacquired by the block ?

Answer»

By using law of conservation of momentumm₁u₁ = (m₁ + m₂)v

v = m₁u₁ / (m₁ + m₂)= (10 × 10^-3 kg × 400 m/s) / [(10 + 900) × 10^-3 kg]= 4.395 m/s

Velocity acquired by the wooden block is 4.395 m/s



Discussion

No Comment Found

Related InterviewSolutions