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15. A uniform chain of length 2 m is kept on atable such that a length of 60 cm hangs freelyfrom the edge of the table. The total mass ofthe chain is 4 kg. What is the work done inpulling the entire chain onto the table ?(g = 10 m/s)1) 7.2J273.63) 120J4) 1200

Answer»

First of all let assume mas of chain hanging down is "m" while it's length is "l".Total length of chain "L" while total mass is "M".So from the given data we know that M is equal to 4kgtotal length=L=2ml = 60 cm = 0.6 m As we know that 1 meter=100cmThus we know thatm= I/L * Mm=(0.6/2 )* 4= 1.2kgIn order to findout the tension of strain the formula is =mg =1.2*10 = 12 Newtonwe know that the tension is equal to force required and 0.6 is actually the displacement because that part is hangingSo also we knowwork done= force*displacementnow as we have readings so just put the valueWork done = 12 * 0.6 = 7.2 JSo the work done in this case will be equal to7.2 J.



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