1.

0.15g of an organic compound (A) gave 0.33g of CO_(2) and 0.18g of H_(2)O. The molecular weight of (A) is 60. The compound (A) on dehydration gave a hydrocarbon (B) containing 85.7% of C. (B), on successive treatment with hydriodic acid and silver hydroxide gave a product (C ), isomeric with (A). Find structural formula of (A), (B) and (C )

Answer»

Solution :`[((A) CH_(3)CH_(2)CH_(2)OH),((B) CH_(3)CH= CH_(2)),((C ) CH_(3)CH(OH)CH_(3))]`


Discussion

No Comment Found

Related InterviewSolutions