1.

0.15g of an organic compound gave 0.12g of silver bromide by the Carius method. The percentage of bromine in the compound is :

Answer»

`42.06`<BR>`38.96`
`24.08`
`34.04`

Solution :`UNDERSET(188)(AgBr)=underset(80)(Br)`
`188g` of `AgBr` CONTAIN bromine `=80G`
`0.12g` of `AgBr` contain bromine `=(80)/(188)xx0.12`
`=0.051g`
PERCENTAGE of bromine `=(0.051)/(0.15)xx100`
`=34.04%`


Discussion

No Comment Found

Related InterviewSolutions