1.

0.16 gm of a dibasic acid require 25 ml of decinormal NaOH solution for complete neutralization. The moleucular weight of the acid

Answer»

32
64
128
256

Solution :`(0.16)/(X)xx(1000)/(25)=(1)/(10)implies(6.4)/(x)=(1)/(10) thereforex=64`
MOL. Wt.=`64xx2=128`.


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