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0.16 gm of organic acid required 25 ml of (N)/(10) NaOH for complete neutralization. (M. wt of acids is 128). Then the basicity of acid is |
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Answer» `(wt)/("Gewt")= 25 XX 0.1 xx 10^(-3)` `(0.16)/("Gewt") = 25 xx 0.1 xx 10^(-3)` valancy(basicety) = `("Mol.wt")/("Gewt")=2` |
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