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| 1. |
0.2 kg of water vanar al 100^(@)C is admitted into a mixture consisting of 5 kg of water and 3 kg of ice. What will happen? Neglect radiative losses. |
| Answer» Solution :The heat liberated in the PROCESSES of condensation of water vapour and of COOLING of water down to the melting point of ice is `Q=m_(3) (L+c Deltat)=5.2xx10^(5)J`. This is not enough to melt all the ice. For this the required heat is `Q_(m)=m_(2)lambda=10^(6)J`. THEREFORE the ice will only partially melt. | |