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InterviewSolution
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0.25 mole of propane is subjected to combustion. If this reaction is used for making a fuel cell, the number of moles of electrons involved in each half cell for this amount of propane will be |
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Answer» Solution :No of moles of electrons involved for 1 MOLE of `C_(3)H_(8)=20` `therefore`. No. of moles of electrons involved for 0.25 mole of `C_(3)H_(8)=5`. |
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