1.

0.2595 g of an organic substance in a quantitative analysis yielded 0.35 g of the barium sulphate. The percentage of sulphur in the subtance is

Answer»

`18.52 G`
`182.2 g`
`17.5 g`
`175.2 g`

Solution :`%` of `S = 32/233 XX (" w.t of " BaSO_(4))/(" w.t of ORGANIC COMPOUND") xx 100`
`= 32/233 xx (0.35)/(0.2595) xx 100 = 18.52% gm`.


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