0.29 g of hydrocarbon when burnt completely in oxygen produces 448 ml

1.	0.29 g of hydrocarbon when burnt completely in oxygen produces 448 ml of carbon dioxide at STP. From the information, calculate the i) mass of carbon dioxide formedii) mass of element carbon in carbon dioxide iii) mass of hydrogen in hydrocarbon.
Answer» i) Gram molecular weight of carbon dioxide = 12 + 2 × 16g = 44 g. 22.4 litres of CO₂ at STP weighs 44 g. The weight of 448 ml of CO₂ at STP = \(\frac{44}{22400}\) × 448 = 0.88 g ii) 44g of CO₂ contains 12 g of carbon. The amount of carbon present in 0.88 g of CO₂ = \(\frac{12}{44}\) × 0.88 = 0.24 g iii) Weight of hydrogen = Weight of hydrocarbon – Weight of carbon = 0.29 – 0.24 = 0.05 g

0.29 g of hydrocarbon when burnt completely in oxygen produces 448 ml of carbon dioxide at STP. From the information, calculate the i) mass of carbon dioxide formedii) mass of element carbon in carbon dioxide iii) mass of hydrogen in hydrocarbon.

Answer»

i) Gram molecular weight of carbon dioxide = 12 + 2 × 16g = 44 g.

22.4 litres of CO₂ at STP weighs 44 g.

The weight of 448 ml of CO₂ at STP = \(\frac{44}{22400}\) × 448 = 0.88 g

ii) 44g of CO₂ contains 12 g of carbon.

The amount of carbon present in 0.88 g of CO₂ = \(\frac{12}{44}\) × 0.88 = 0.24 g

iii) Weight of hydrogen = Weight of hydrocarbon – Weight of carbon = 0.29 – 0.24 = 0.05 g

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0.29 g of hydrocarbon when burnt completely in oxygen produces 448 ml of carbon dioxide at STP. From the information, calculate the i) mass of carbon dioxide formedii) mass of element carbon in carbon dioxide iii) mass of hydrogen in hydrocarbon.

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