1.

0.3 g of an acid is neutralised by 40 cm^(3) of 0.125 N NaOH. Equivalent mass of the acid is

Answer»

60
45
30
63

Solution :`40cm^(3)` of 0.125 N NAOH neutralise ACID = 0.3 g
`therefore 1000cm^(3)` of 1 N NaOH will neutralise acid
`=(0.3)/(40)xx(1000)/(0.125)g=60g`
`1000cm^(3)` of 1 N NaOH contain one g ram equivalent of NaOH. It will neutralise one gram equivalent of the acid.
Hence, equivalent WEIGHT of acid = 60


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