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0.3 g of platinichloride of an organic diacidic base left 0.09 g of platinum on ignition. The molecular weight of the organic base isA. 120B. 240C. 180D. 60 |
Answer» Correct Answer - B Let B is the original bese. `2B+H_2(2)PtCl_(6)toB_(2)H_(2)PtCl_(2)overset(Delta)toPt` Ew of `B_(2)H_(2)PtCl_(2)=2B+2+195+6xx35.5` `=2B+410` `("Weight of chlorophatinate")/("Weight of" Pt)=("Ew of salt")/(Ew of Pt)` `(0.3)/(0.09)=(2B+410)/(195)` `B(Ew of base)=120` Mw of `base=Ewxxacidity` `=120xx2=240` |
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