1.

0.30g of an organic compound contaiining C, H and Oxygen an combustion yields 0.44gCO_2 and 0.18g H_2O. If onemol of compound weight 60, then molecular formula of the compound is

Answer»

`C_2H_4O_2`
`C_4H_6O`
`C_3H_8O`
`CH_2O`

SOLUTION :Percentage of `C = 12/44 XX 0.44/0.30 xx 100 = 40%`
Percentage of `H= 12/18 xx 0.18/0.30 xx 100 = 6.6%`
Percentage of `O = 100-(40 + 6.6) = 53.4%`

Hence empirical formula `= CH_2O`
`n = ("Molecular mass")/("Emperical formula mass") =60/30 = 2`
`rArr ` Molecular formula of the compound` = (CH_2O)_2 = C_2H_4O_2`


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