1.

0.45 g an acid (mol wt.=90) required 20 ml of 0.5 N KOH for complete neutralization. Basicity of acid isA. 1B. 2C. 3D. 4

Answer» Correct Answer - B
Normality`=N=(W_(B)xx1000)/(Eq." "wtxxV)`
`therefore"Eq. Wt"=(0.45xx1000)/(0.5xx20)=45`
`therefore"Basicity"=("Molec. Wt")/("Eq. wt")=(90)/(45)=2`


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