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0.53 gm of `Na_(2)CO_(3)` has been dissolved in 100 ml of a sodium carbonate solution. The normality of the solution will beA. `(N)/(5)`B. `(N)/(2)`C. `(N)/(10)`D. N |
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Answer» Correct Answer - C `N=(0.53xx1000)/(53xx100)impliesN=(1)/(10)` So normality of the solution will be `(N)/(10)`. |
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