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Weight of `Ca(OH)_(2)` needed to prepare 250 ml of solution with pH=13A. 0.925 gB. 0.0125 gC. 0.25 gD. 1 g |
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Answer» Correct Answer - A We know, `[H^(+)]=10^(-pH)=10^(-13)` `therefore[OH^(-)]=(10^(-14))/(10^(-13))=10^(-1)` hence, normality of solution=0.1 We know, `w=(NEV)/(1000)=(0.1xx74xx250)/(2xx1000)=0.925gm` |
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