1.

0.45 g of an acid ( mol. Mass = 90 ) is neutralised by 20 mol of 0.5 N NaOH solution. The basicity of the acid is :

Answer»

1
2
3
4

Solution :20 ML of 0.5 N NaOH solution neutraliseacid = 0.45 g
1000 ml of 1 N NaOH solution neutralise acid
`=(0.45 xx 1000 xx 1)/(20 xx 0.5)`
= 45 g
EQ. WT of acid = 45 g
BASICITY `=("Mol. wt")/("Eq. wt ")=(90)/(45)=2`


Discussion

No Comment Found

Related InterviewSolutions