1.

0.5 F of electric current was passed through 5 molar solution of AgNO_(3), CuSO_(4) " and " AlCl_(3) connected in series. Find out the concentration of each of the electrolyte after the electrolysis.

Answer»

SOLUTION :Given : Quantity of electricity, Q = 0.5 F <BR> Concentration of solution, C = 5 M
Solution :
(i) For `AgNO_(3)`
1 mol of `Ag^(+)=1F`
`""0.5F= 0.5` mol of `AgNO_(3)`
Concentration of `AgNO_(3)` after electrolysis
`""=5-0.5`
`""=4.5 M`
(ii) For `CuSO_(4)`
1 mol of `CuSO_(4) " (or) " Cu^(2+)=2F`
2F = 1 M `CuSO_(4)`
`0.5F=1/2 times 0.5=0.25M`
Concentration of `CuSO_(4)` after electrolysis
`""=5-0.25`
`""=4.75M`
(iii) For `AlCl_(3)`
1 mol of `AlCl_(3)" Br "Al^(3+)=3F`
`3F=1M" "AlCl_(3)`
`0.5=1/3 times 0.5`
`""=0.5/3=0.167M`
Concentration of `AlCl_(3)` after electrolysis
`""=5-0.167`
Concentration of `AlCl_(3)` after electrolysis
`""=4.833M`


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