1.

0.5 M ammonium benzoate is hydrolyzed to 0.25 percent, hence its hydrolysis constant is

Answer»

`2.5 xx 10^(-5)`
`1.5 xx 10^(-4)`
`3.125 xx 10^(-6)`
`6.25 xx 10^(-14)`

Solution :`{:(C_(6)H_(5)COONH_(4),RARR,C_(6)H_(5)COO^(-),+,NH_(2)^(+)),(0.5 - (.25)/(100),,(.25)/(100),,(.25)/(100)):}`
According to Ostwald dilution law.
`K = (ALPHA^(2)C)/(1-alpha) "" ( :. alpha = (.25)/(100))`
`K = alpha^(2)C "" ( because 1- alpha = "Very SMALL")`
`K = (0.25)/(100) xx (0.25)/(100)xx 0.5 , K = 3.125 xx 10^(-6)`


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