Saved Bookmarks
| 1. |
`0.5` mole of `H_(2)SO_(4)` is mixed with `0.2` mole of `Ca(OH)_(2)`. The maximum number of mole of `CaSO_(4)` formed is:A. `0.2`B. `0.5`C. `0.4`D. `1.5` |
|
Answer» Correct Answer - A Eq. of `H_(2)SO_(4)= 0.5xx2=1.0`, Eq. of `Ca(OH)_(2)=0.2xx2=0.4`, Thus, Eq. of `CaSO_(4)` formed `=0.4` `:. "Mole of" CaSO_(4) "formed" =(0.4)/(2)=0.2` |
|