1.

0.6 g of a solute is dissolved in 0.1 littre of a solvent which develops an osmotic pressure of 1.23 atm at 27^(@)C. The molecular mass of the substance is

Answer»

`149.5 "g mole"^(-1)`
`120 "g mole"^(-1)`
`430 "g mole"^(-1)`
None of these

Solution :`m=(WRT)/(PV)=(0.6xx0.082xx300)/(1.23xx0.1)=120`


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