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`0.63 g` of diabasic acid was dissolved in water. The volume of the solution was made `100 mL`. `20 mL` of this acid solution required `10 mL` of `N//5 NaOH` solution. The molecular mass of acid is:A. `63`B. `126`C. `252`D. `128` |
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Answer» Correct Answer - B Meq. of acid in `20 mL=`Meq.of`NaOH` `10xx(1)/(5)=2` `:.` Meq. of acid in `100mL=(2xx1000)/(20)=10` or `(w)/(M//2)xx1000=10` `(0.63)/(M//2)xx1000=10` or `M=126` |
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