0.635 g Cu was dissolved in 5.0 mL hot 60% HNO_(3)(sp. gr. = 1.5). When the reaction came to an end, the volume of the solution was adjusted to 250.0 mL, What is the normality of the solution with respect to HNO_(3) ? (Cu= 63.5)

0.635 g Cu was dissolved in 5.0 mL hot 60% HNO_(3)(sp. gr. = 1.5). Whe

1.	0.635 g Cu was dissolved in 5.0 mL hot 60% HNO_(3)(sp. gr. = 1.5). When the reaction came to an end, the volume of the solution was adjusted to 250.0 mL, What is the normality of the solution with respect to HNO_(3) ? (Cu= 63.5)
Answer» 0.256 N 0.126 N 0.324 N 0.425 N Solution :0.635 g Cu was dissolved in 5.0 mL hot 60% `HNO_(3)` (specific gravity = 1.5) The following reaction occurs: `Cu + 4HNO_(3) =Cu(NO_(3))_(2) + 2NO_(2) + 2H_(2)O` Molecular weight of `HNO_(3) = (1 + 14 + 48) = 63` In equivlent weight = 63/1 = 63. 63.5 g of Cu reacts with `4 xx 63 = 252 g` of `HNO_(3)` `therefore 0.635` g of Cu reacts with `252/63.5 xx 0.635 g` of `HNO_(3) = 2.52 g` of `HNO_(3)` `=1.98/63` g equilvaent of `HNO_(3)` `therefore 1000 mL` of `HNO_(3)` contains `=1.98/63 xx 1000/250 = 0.126`g equivalent of `HNO_(3)` The normality of the solution with RESPECT to `HNO_(3)` is 0.126 (N)