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`0.7 g "of" Na_(2)CO_(3).xH_(2)O` were dissolved in water and the volume was made to `100 mL, 20 mL` of this solution required `19.8 mL "of" N//10 HCl` for complete neutralization. The value of `x` is:A. `7`B. `3`C. `2`D. `5` |
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Answer» Correct Answer - C Meq. of `Na_(2)CO_(3).xH_(2)O "in" 20 mL=19.8xx(1)/(10)` `:.` Meq.of `Na_(2)CO_(3).xH_(2)O "in" 100 mL=19.8xx(1)/(10)xx5` `:. (w)/(E )xx1000=19.8xx(1)/(10)xx5` or `(0.7)/(M//2)xx1000=(19.8)/(2)` `:. M= 141.41` `23xx2+12+3xx16+18x=141.41` `:. x=2` |
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