0.75 " mol of "solid `X_(4)` and 2 " mol of "gaseous `O_(2)` are heated to react completely in sealed vessel to produce only one gaseous compound Y. After the compound is formed the vessel is brought to the initial temeprature, the pressure is found to half the inital pressure. Calculate the molecular formula of compound?

0.75 " mol of "solid `X_(4)` and 2 " mol of "gaseous `O_(2)` are heate

1.	0.75 " mol of "solid `X_(4)` and 2 " mol of "gaseous `O_(2)` are heated to react completely in sealed vessel to produce only one gaseous compound Y. After the compound is formed the vessel is brought to the initial temeprature, the pressure is found to half the inital pressure. Calculate the molecular formula of compound?
Answer» `underset(`{:(i nitial mol),(Fi nal mol):}](0.75)(2)(0) `)(X_(4)+O_(2)toY)` Initial pressure is due to `O_(2)` (2 mol), because `X_(4)` is solid and final pressure is due to Y only (a mol). Temperature remains constant. Now, `Pprop" mol of "O_(2)prop2` `(P)/(2)prop" mol of "Ypropa` In other words, only 1 " mol of "Y is formed. The mol ratio of `X_(4):O_(2)` in `Y=0.75:2` Ratio of atoms of X and O in `Y=4xx0.75:2xx2=3:4` Thus, Y is `X_(3)O_(4)`

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