1.

0.76gm of the silver salt of a diabasic acid was ignited. It gave 0.54gm of pure silver. The molecular mass of acid is ........ x10.

Answer»


Solution :`E = (("MASS of silver SALT")/("mass of silver") xx 108-107)`
`=((0.76)/(0.54) xx 108-107)` , E = 45
Molecular mass = `45 xx 2` = 90


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