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0=¢+X9-xg (M)O=6+xg—2C 0% Hfllfb-u:fi' plkB) bkl ! |
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Answer» 2x²-3x-5=0 x= -b±√(b²-4ac)--------------2a= -(-3)±√[(3²)-4(2)(-5)]----------------------2(2)=3±√(9+40)------------4=3±√49--------4=3±7 = -4 or 10----- = --------- The descriminant of the quadratic equation is given by b2– 4acHere a = 2, b = – 6, c = 3⇒b2– 4ac = (– 6)2– 4(2)(3) = 36 – 24 = 12Since b2– 4ac > 0, the roots are real and distinct |
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