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01. Factorise : (x + y)³– (x³ + y³) |
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Answer» -step explanation:Consider, (X+y) 3 −(x 3 +y 3 )=(x+y) 3 −[(x+y)(x 2 −xy+y 2 )] =(x+y)[(x+y) 2 −(x 2 −xy+y 2 )] =(x+y)[(x 2 +2xy+y 2 )−(x 2 −xy+y 2 )] =(x+y)(3XY)CLEARLY, 3xy is FACTOR of (x+y) 3 −(x 3 +y 3 ) |
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