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02. Rahul runs for 20mins at the speed of 20km/hr. After which he gets tired, he still manages to run for 10 mins but at a lesser speed of 10km/hr. How muchdistance did Rahul cover?(2)​

Answer»

To begin with, let us ignore car A. Car B and car C TRAVEL in opposite directions.Their relative SPEED = Sum of the two speeds = 45 + 54 kmph = 99kmph.= 99 * 518m/s = 552m/s = 27.5m/sThe relative distance = 220m. So, time they will TAKE to cross each other = 22027.5 = 8 secondsNow, car A has to overtake car B within 8 seconds. The relative distance = 50m=> Relative speed should be at least 508m/s = 6.25 m/s.=>6.25 * 185kmph = 22.5 kmphThe question is " If car A decides to overtake Car B before cars B and C cross each other, what is the minimum speed at which car A must travel? "Car B travels at 45kmph, so car A should travel at at least 45 + 22.5 = 67.5kmph.Hence, the answer is 67.5kmph.Explanation:similar to your question



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