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06. Find the area of a tringle two sides of which are 18 cm and 10 cm and the perimeter is42 cm |
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Answer» Answer: AREA of the triangle is 21√11 Step-by-step EXPLANATION: a= 18 cm b= 10 cm perimeter= 42 cm semi perimeter 's'= perimeter/2 s = 42/2 s = 21 cm s = a+b+c/2 21 = 18+10+c/2 21 = 28 +c/2 21×2 = 28 + c 42-28 = c c = 14 area of a triangle = √s(s-a)(s-b)(s-c) = √21(21-18)(21-10)(21-14) = √21×3×11×7 = √7×3×3×11×7 = 7× 3 √11 = 21√11 plz mark this answer as brainliest |
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