1.

1.0 g of a non-electolyte solute (molar mass 250 g mol^(-1)) was dissolved in 51.2 g of benzene. If the K_(f) for benzene is 5.12 K kg mol^(-1), the freezing point of benzene will be lowerd by :

Answer»

0.2 K
0.4 K
0.3 K
0.5 K.

Solution :`DeltaT_(f)=(K_(f)xxW_(B))/(M_(B)xxW_(A))`
`=((5.12 KG mol^(-1))XX(1.0g))/((250gmol^(-1))xx(0.0512kg))=0.4 K`


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