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InterviewSolution
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1.0 g of an oxide of metal M contained 0.5 g of M and 4.0 g of another oxide of M contained 1.6 g of M. These data illustrate the |
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Answer» Law of RECIPROCAL proportion Mass of oxygen = 1.0-0.5 = 0.5 g Mass of oxygen which COMBINES with 0.5 g of metal = 0.5 g Mass of oxygen in second oxide = 4.0 - 1.6 = 2.4 g Mass of oxygen which combines with 1.6 g of metal = 2.4 g Mass of oxygen which combines with 0.5 GOF metal ` = (2.4)/(1.6) xx 0.5 = 0.75 g ` Ratio of different masses of oxygen combining with 0.5 g of metal 0.5 : 0.75 2 : 3 sicne it is simple ratio ,it illustrates law of multiple proportions . |
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