1.

1.0 g of magnesium is burnt with 0.56 g O_(2) in a closed vessel. Which reactant is left in excess and how much ? (At. Wt. of Mg = 24, O = 16)

Answer»

Mg, 0.16 g
`O_(2),0.16g`
`Mg,0.44g`
`O_(2),0.28g`

SOLUTION :`underser(" = 48")underset(2xx24g)(2Mg)+underset(32g)(O_(2))rarr2MgO`
1 g of Mg needs `O_(2)=(32)/(48)g=(2)/(3)g=0.67g` which is not present.
`0.56` g of `O_(2)` will react with Mg
`=(48)/(32)xx0.56=0.84`
Thus, Mg is left in excess and amount left
`=1-0.84g=0.16g`


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